Final answer:
The initial velocity 'v' is the coefficient of the 't' term in the quadratic function h(t). At t=0, the equation simplifies, and 'v' is the initial velocity with which the diver left the platform.
Step-by-step explanation:
The student's question deals with a quadratic equation representing the height of a platform diver above the water as a function of time, h(t) = -16t^2 + vt + 10. Here, initial velocity 'v' is the coefficient of the linear term 't' in the equation. To find the initial velocity, we look at the equation at the moment the diver leaves the platform, which is when t = 0. At this instant, the only term that affects the height is the constant term 10 feet, which represents the height of the platform above the water. However, since we have to find the velocity 'v', we look at the term vt in the equation. The initial velocity is the velocity of the diver at the moment of the leap (t = 0), which is the value of 'v' because the height h(0) = -16(0)^2 + v(0) + 10 simplifies to 10 feet, the height of the platform, with no influence from the velocity term at that specific moment.