450,747 views
37 votes
37 votes
What is the number of chloride ions (Cl-) in 250 mL of a 0.2M magnesium chloride solution?

Thank you.

User Tahesha
by
3.5k points

1 Answer

28 votes
28 votes

To determine the number of chloride ions (Cl-) in 250 mL of a 0.2M magnesium chloride solution, we need to use the formula:

number of ions = concentration (M) * volume (L) * Avogadro's number

In this case, the concentration is 0.2 M, the volume is 250 mL, and Avogadro's number is 6.022 x 10^23 ions/mol.

To convert the volume from milliliters to liters, we can divide the volume by 1000. This gives us a volume of 250 mL / 1000 mL/L = 0.250 L.

Substituting these values into the formula above, we get:

number of ions = 0.2 M * 0.250 L * 6.022 x 10^23 ions/mol

= 0.2 M * 0.250 L * 6.022 x 10^23 ions/mol

= 1.204 x 10^23 ions

Therefore, there are approximately 1.204 x 10^23 chloride ions (Cl-) in 250 mL of a 0.2M magnesium chloride solution.

User Adwoa
by
2.4k points