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1. Which quadratic has x-intercepts at (-3, 0) and (5, 0)?

a) f (x) = (x - 3)(x + 5)
b) f (x) = x^2 - 3x + 5
c) f (x) = (x + 3)(x - 5)
d) f (x) = x^2 + 3x - 5

1 Answer

6 votes

Answer:

c

Explanation:

Since the x-intercepts of the quadratic function are (-3,0) and (5,0), so its roots are
x=-3 and
x=5

So, the quadratic function contains the linear factors
(x+3) and
(x-5). Then, the quadratic function in the factored form would be, where a is a real number:


f(x)=a(x+3)(x-5)

For simplicity, assume that
a=1 and the quadratic function becomes:


f(x)=(x+3)(x-5)

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