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the threshold frequency for gold is 1.20x 1015 hz. if the total energy emitted by a sample of gold is 12.2 kj, calculate the number of atoms present in the sample? (assume each atom emits one photon)

User Inkriti
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Answer: Number of atoms: 1.82 x 10^21

Step-by-step explanation:

To calculate the number of atoms present in the sample of gold, we can use the equation:

E = Nhf

Where:

E is the total energy emitted by the sample,

N is the number of atoms,

h is the Planck's constant (approximately 6.626 x 10^-34 J·s),

f is the frequency of each photon.

We are given the total energy emitted by the sample as 12.2 kJ, which we need to convert to joules:

12.2 kJ = 12.2 x 10^3 J

The frequency of each photon is related to the threshold frequency by the equation:

f = threshold frequency

Substituting the given values:

f = 1.20 x 10^15 Hz

Now we can rearrange the equation E = Nhf to solve for N:

N = E / (hf)

Substituting the values:

N = (12.2 x 10^3 J) / ((6.626 x 10^-34 J·s) * (1.20 x 10^15 Hz))

Performing the calculation:

N ≈ 1.82 x 10^21

Therefore, the number of atoms present in the sample is approximately 1.82 x 10^21.

User Minwoo
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