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Find the volume formed by rotating about the y-axis the region enclosed by:

x = 10y and y³ = x with y ≥ 0

Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis.
y=0, y=cos(6x),x = π/12. x=0 about the axis y=-1

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Answer: the volume of the solid obtained by rotating the region bounded by the curves y=0y=0, y=cos⁡(6x)y=cos(6x), x=π12x=12π​, and x=0x=0 about the axis y=−1y=−1 is approximately 0.02160.0216.

Step-by-step explanation:

To find the volume formed by rotating the region enclosed by the curves x=10y and y^3=x around the y-axis, we can use the method of cylindrical shells. First, we sketch the region and the axis of rotation, noting that it is bounded by y=0, y=x^(1/3), and x=10y.

To apply the cylindrical shells method, we express the volume of each shell as a function of the height y. The radius of each shell is given by r=10y since it is the distance from the y-axis to the curve x=10y. The height of each shell is h=x^(1/3)-0=x^(1/3).

Therefore, the volume of each shell is dV=2π(10y)(y^(1/3))dy = 20πy^(4/3)dy.

To find the total volume, we integrate this expression over the range of y values that define the region: V=∫(0 to 1)(20πy^(4/3))dy = 60π/7.

Hence, the volume formed by rotating the region enclosed by x=10y and y^3=x around the y-axis, with y≥0, is 60π/7.

To find the volume of the solid obtained by rotating the region bounded by y=0, y=cos(6x), x=π/12, and x=0 about the axis y=-1, we can again use the method of cylindrical shells.

First, we sketch the region and the axis of rotation, noting that it is bounded by y=0, y=cos(6x), x=π/12, and x=0.

To apply the cylindrical shells method, we express the volume of each shell as a function of the height y. The radius of each shell is given by r=1+cos(6x) since it is the distance from the line y=-1 to the curve y=cos(6x). The height of each shell is h=π/12-x.

Therefore, the volume of each shell is dV=2π(1+cos(6x))(π/12-x)dx.

To find the total volume, we integrate this expression over the range of x values that define the region: V=∫(0 to π/12) 2π(1+cos(6x))(π/12-x)dx ≈ 0.0216.

Thus, the volume of the solid obtained by rotating the region bounded by y=0, y=cos(6x), x=π/12, and x=0 about the axis y=-1 is approximately 0.0216.

User Leo Silence
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