The solutions for x and y as ordered pairs are (19, 4) and (7, 9).
Let's denote the larger integer as x and the smaller integer as y. Write down the two equations based on the problem.
The two equations are: 2x + 3y = 46 and x² + 4x = 20y + 5.
Rearrange the first equation to solve for x.
The rearranged first equation is
.
Substitute x from the rearranged first equation into the second equation.
The substituted second equation is
.
Simplify the substituted second equation.
The simplified equation is y² - 23y + 36 = 0.
Solve the quadratic equation y² - 23y + 36 = 0 for y.
The solutions for y are y = 4 and y = 9.
Substitute each solution for y back into the rearranged first equation to solve for x.
The solutions for x are x = 19 when y = 4 and x = 7 when y = 9.