Question

9.4.1: hamming code. to encode 8-bit bytes, hamming code requires 4 parity bits at positions 1, 2, 4, and 8. the table shows which positions are covered by which parity bit.

Answer 1

Hamming code is used to encode 8-bit bytes by adding 4 parity bits at specific positions.

Step-by-step explanation:

Hamming code is used to encode 8-bit bytes for error detection and correction. In Hamming code, 4 parity bits are added at positions 1, 2, 4, and 8 to the original data bits. These parity bits are calculated based on the values of the data bits in specific positions.

For example, let's say we want to encode the 8-bit byte 11001010. The parity bits for this byte are calculated as follows:

1. Parity bit at position 1: 1 + 0 + 1 + 0 = 0 (even parity)
2. Parity bit at position 2: 1 + 0 + 0 + 1 = 0 (even parity)
3. Parity bit at position 4: 1 + 0 + 0 + 0 + 1 = 1 (odd parity)
4. Parity bit at position 8: 1 + 1 + 0 + 1 + 0 + 1 = 0 (even parity)

So the encoded byte with the added parity bits would be 01101010.