Final answer:
To determine the number of grams of NH3 needed to react with 2g of K2PtCl4, we use the balanced chemical equation and molar mass of NH3. The mass of NH3 required is 0.216 g.
Step-by-step explanation:
To determine the number of grams of NH3 needed to react with 2g of K2PtCl4, we need to use the balanced chemical equation and the molar mass of NH3. The balanced equation is:
K2PtCl4 + 2NH3 → Pt(NH3)2Cl2 + 2KCl
From the equation, we see that 2 moles of NH3 are required to react with 1 mole of K2PtCl4. The molar mass of NH3 is 17.03 g/mol. We can set up a proportion to find the mass of NH3:
2g K2PtCl4 / (254.531 g/mol K2PtCl4) = x g NH3 / (17.03 g/mol NH3)
Solving for x, we get x = 0.216 g NH3.