Question

How many grams of beryllium chloride (BeCl2) are needed to make 125 g of a 22.4% solution?

Answer 1

Answer: 28 grams

Step-by-step explanation:

calculation of the mass :

x grams = (22.4/100) * 125 grams

to solve for x otherwise known as how many grams we need :

x grams = (22.4/100) * 125 grams

x grams = 0.224 * 125 grams

x grams = 28 grams