Question

How any kPa is 2L of gas if it takes 2.55L at 146kPa?

Answer 1

Answer: it will have a pressure of approximately 371.73 κPa.

We know that According to Boyle's Law

P1 ×V1 = P2 ×V2

therefore in order to find P2

P2 =
`(P1 X V1)/(V2)` --------------------(I)

where

P1 = initial pressure

V1 = initial volume

P2 = final pressure

V2 = final volume

here

P1(initial pressure) = 146 kPa

V1(initial volume) = 2.55 L

V2(final volume) = 2 L

Now putting the given values in equation (I) :

P2 = (146 kPa × 2.55 L) / 2 L

P2 = 371.73 kPa

Therefore, 2 L of gas, when it takes 2.55 L at 146 kPa, will have a pressure of 371.73 kPa.