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Simplify √(x^2-8x+16) if -4\leqx<4

Simplify √(x^2-8x+16) if -4\leqx<4
177k views
2 votes
Simplify
√(x^2-8x+16) if -4
\leqx<4

User Piovezan
by
9.0k points

1 Answer

4 votes

Answer:

x = 4

Explanation:


√((x -4)(x - 4)\\)

x - 4 = 0

x = 4

User Luc Bos
by
7.7k points
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