Question

100 ml of 4.0 c liquid water is heater until its temp is 37. calculate the amount of heat energy needed to cause this rise in temperature

Answer 1

First we need the mass of water using density
Density if H2O= 1 g/ml
Mass = Density x Volume
Substitute
Mass = 1 x 100 = 100g

Use the formula Q=mcΔT
m=100g
c=4.18 J/g.°C
ΔT= 37 - 4 = 33 °C
Substitute
Q= 100 x 4.18 x 33 = 13794 J
Hope this helps