Answer: g(x) = 6*x^2 + 15
Explanation:
Suppose that we have a function y = f(x)
A vertical stretch by a factor of K is written as:
g(x) = K*f(x).
In this case, we have f(x) = 2*x^2 + 5.
And we know that g(x) is a f(x) after a stretch by a factor of 3.
Then we get:
g(x) = 3*f(x) = 3*(2*x^2 + 5) = 3*2*x^2 + 3*5 = 6*x^2 + 15
g(x) = 6*x^2 + 15