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In a sample of 560 adults, 336 had children. Construct a 95% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three places < p
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In a sample of 560 adults, 336 had children. Construct a 95% confidence interval for the true population proportion of adults with children.

Give your answers as decimals, to three places

< p

User Saqib Rezwan
by
8.6k points

1 Answer

4 votes

Answer:


\{0.559,0.641\}

Explanation:


\displaystyle CI_(95\%)=(336)/(560)\pm1.96\sqrt{((336)/(560)(1-(336)/(560)))/(560)}\approx\{0.559,0.641\}

User Arkadiy Kukarkin
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