Question

Period of y=-1/3sin2x

Answer 1

π

Explanation:

In the standard form equation for sine:

`y = a\cdot \sin(b(x-c)) + d`,

the period, or wavelength, of the function is:

`\frac{2\pi}b`

In the given equation:

`y=-(1)/(3)\sin(2x)`

we can identify
`b` as
`2`.

Using this
`b`-value, we can solve for the period of the wave.

`\begin{aligned} \text{period} = (2\pi)/(b) &= \frac{2\pi}2 \\ &= \boxed{\pi} \end{aligned}`

So, the period of

`y=-(1)/(3)\sin(2x)`

is π.