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Calculate the molarity of a solution, when 20.2g of potassium nitrate (kno3) is dissolved in 250.0ml of water

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Answer:

To calculate the molarity (M) of a solution, you need to know the moles of solute and the volume of the solution in liters.

First, let's calculate the moles of potassium nitrate (KNO3) using its molar mass. The molar mass of KNO3 is the sum of the atomic masses of potassium (K), nitrogen (N), and three oxygen (O) atoms:

Molar mass of KNO3 = (1 × atomic mass of K) + (1 × atomic mass of N) + (3 × atomic mass of O)

Using the atomic masses from the periodic table:

Atomic mass of K = 39.10 g/mol

Atomic mass of N = 14.01 g/mol

Atomic mass of O = 16.00 g/mol

Molar mass of KNO3 = (39.10 g/mol) + (14.01 g/mol) + (3 × 16.00 g/mol)

Molar mass of KNO3 ≈ 101.10 g/mol

Next, let's calculate the moles of KNO3:

Moles = mass / molar mass

Moles = 20.2 g / 101.10 g/mol

Moles ≈ 0.20 mol

Now, we have the moles of KNO3 and the volume of the solution in liters (250.0 ml = 0.250 L). Let's calculate the molarity:

Molarity = moles / volume (in liters)

Molarity = 0.20 mol / 0.250 L

Molarity = 0.80 M

Therefore, the molarity of the solution is approximately 0.80 M.

Step-by-step explanation:

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