Question

A spinner is spun that has 15 equal-sized sections numbered 1 to 15. What is the probability the spinner lands on an odd

number?

Answer 1

8/15

Explanation:

There are 15 equal-sized sectors:

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15

The odd ones are:

1, 3, 5, 7, 9, 11, 13, 15

There are 8 odd numbered sectors.

p(event) = (number of desired outcomes)/(total number of possible outcomes)

p(odd) = 8/15