Answer:
5.859 grams
Step-by-step explanation:
CaO + 2Na → Na₂O + Ca
From the above reaction, 2 moles of Na react with 1 mole of CaO to produce 1 mole of Na₂O and 1 mole of Ca
We have 4.35 g of Na, which is 0.189 mol of Na
As no additional information is given, we shall consider Na as the limiting reagent.
If 2 moles of Na are required to produce 1 mole of Na₂O
0.189 moles produces 0.189/2 = 0.0945 mol of Na₂O
Mass of Na₂O = Moles of Na₂O * Molar mass of Na₂O
= 0.0945 mol * 62 g/mol
= 5.859 g