Question

Question 6 of 10

The circle below is centered at the point (-1, 2) and has a radius of length 3.
What is its equation?
O A. (x + 2)2 + (y-1)² =
3²
B. (x-1)2 + (y + 2)² = 9
O C. (x + 1)2 + (y-2)² = 9
D. (x-2)² + (y+ 1)² =
32

Answer 1

C. (x + 1)² + (y-2)² = 9

Explanation:

You want the equation of the circle centered at (-1, 2) with radius 3.

Circle equation

The equation of a circle centered at (h, k) with radius r is ...

(x -h)² +(y -k)² = r²

For (h, k) = (-1, 2) and r=3, this is ...

(x -(-1))² +(y -2)² = 3²

(x +1)² +(y -2)² = 9 . . . . . . matches choice C

<95141404393>