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What are the solutions of the quadratic equation 2x^2-16x+32=0

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Answer: x=4

Explanation:

0=2x²-16x+32 >Take out GCF

0=2(x²-8x+16) >Find 2 numbers that multiple to last term, +16,

but add to middle term, -8

-4 and -4 multiply to +16 and add to -8

put -4 and -4 into factored form

0=2(x-4)(x-4) >Divide both sides by 2

0=(x-4)(x-4) >Normally you would set both parenthesis to 0

but they are the same so set the x-4=0

x-4=0

x=4

User Sterling Duchess
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