Final answer:
The mass of 9.2 moles of lithium carbonate is 679.70 grams, calculated by multiplying the number of moles by the molar mass of lithium carbonate, which is 73.88 g/mol.
Step-by-step explanation:
To calculate the mass of 9.2 moles of lithium carbonate (Li2CO3), we must first determine its molar mass. Using the periodic table, we can find the molar mass of lithium (Li) is 6.94 g/mol, carbon (C) is 12.01 g/mol, and oxygen (O) is 16.00 g/mol. Lithium carbonate contains two lithium atoms, one carbon atom, and three oxygen atoms, so its molar mass can be calculated as follows:
Molar mass of Li2CO3 = (2 × 6.94 g/mol) + (12.01 g/mol) + (3 × 16.00 g/mol) = 73.88 g/mol
Once the molar mass is found, the mass of the substance can be calculated by multiplying the molar mass by the number of moles:
Mass = 9.2 moles × 73.88 g/mol = 679.70 g
Therefore, the mass of 9.2 moles of lithium carbonate is 679.70 grams.