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Chapter 7 Lesson 2 Solving Quadratics by Factoring

Chapter 7 Lesson 2 Solving Quadratics by Factoring-example-1

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Explanation:

1. x(x+2) = 0

It is either x = 0, or x+2 = 0, so we simplify to x=0, -2

2. (7x+2)(5x-4)=0

Same thing, 7x+2=0 and 5x-4=0, so x = -2/7 or 4/5

3. x^2-14x+45=0

Now we have something different, so we have to factor this to:

(x-9)=0 and (x-5)=0, and now we can simplify this to x=9,5

4. x^2+13x=-42

We can't factor this yet until one side is equal to 0, so we move "-42" to the other side to form x^2+13x+42.

We factor this to get (x+6)=0, and (x+7)=0, so x=-6,-7

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