Question

The diagram shows an athlete crossing the finishing line in a race. as she crosses the finishing line, her speed is 10 m/s. she slows down to a speed of 4 m/s.

a)the mass of the athlete is 71 kg. calculate the impulse applied to her as she slows down.

Answer 1

The impulse applied to the athlete as she slows down is 28 N*s.

Step-by-step explanation:

To calculate the impulse applied to the athlete as she slows down, we can use the equation:

impulse = force * time

Since the force applied to the athlete is equal to her mass times her acceleration, we can also express the impulse as:

impulse = mass * (vf - vi) / time

Plugging in the values given in the question, we get:

impulse = 71 kg * (4 m/s - 10 m/s) / time

Solving for impulse, we get:

impulse = 28 N*s

Therefore, the impulse applied to the athlete as she slows down is 28 N*s.