482,116 views
5 votes
5 votes
Where do the asymptotes occur in

y = 1/3 cot 2x

how can i know?
someone help!

User Darold
by
2.3k points

1 Answer

23 votes
23 votes

Answer:


\displaystyle{x=(\pi)/(2)n} for n is any integers

Explanation:

To know the asymptotes, first, we must know values of x that we turn y-value into an undefined value.

We know that:


\displaystyle{\cot x = (1)/(\tan x)}

Now we have to find value of x that turns the identity above into undefined value, and that is
\displaystyle{x=n\pi} where n is any integers. (This gives 1/0 for all x = nπ)

Therefore, a function
\displaystyle{\cot x} has asymptote lines at
\displaystyle{x=n \pi} for n is integers.

If we consider the given problem:


\displaystyle{y=(1)/(3)\cot 2x}

We have to find values of x that turn y-value undefined. We know that
\displaystyle{x=n\pi} is asymptotes for
\displaystyle{\cot x}. Therefore,
\displaystyle{2x=n\pi} has to be asymptotes for
\displaystyle{y=(1)/(3)\cot 2x}.

Hence, the asymptotes occur at
\displaystyle{x=(\pi)/(2)n} by solving the equation and for n is any integers.

User Xavi Rigau
by
2.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.