Question

Which equation is an equation of a circle with a radius of 2 and its center is at (4,

-2)?
(x-4)² + (y + 2)² = 4
(x-4)^2 + (y + 2)² = 2
(x+4)² + (y-2)² = 4

Answer 1

The equation of a circle with a radius of 2 and its center at (4, -2) is:

(x - 4)² + (y + 2)² = 4

Therefore, the correct equation is:

(x - 4)² + (y + 2)² = 4

Answer 2

(x - 4)² + (y + 2)² = 4

Explanation:

Equation of circle:

r = 2 ;

Center (h, k) = (4 , -2)

`\boxed{ (x - h)^2 + (y - k)^2 = r^2}`

(x - 4)² + (y -[-2])² = 2²

(x - 4)² + (y + 2)² = 4