Answer:
The balanced equation tells us that 2 moles of sodium hydroxide react with 1 mole of sulfuric acid. Therefore, to react with 1.30 moles of sulfuric acid, we need:
$2 \times 1.30 = 2.60$ moles of sodium hydroxide.
To convert moles of sodium hydroxide to mass, we need to use its molar mass. The molar mass of sodium hydroxide is:
$1 \times 23.0 + 1 \times 16.0 + 1 \times 1.0 = 40.0$ g/mol.
Therefore, the mass of sodium hydroxide needed is:
$2.60 \text{ moles} \times 40.0 \text{ g/mol} = 104 \text{ g}$.
Answer: 104 g (with 3 significant figures).