Question

4. A store sells two buckets: small and large.

Small Bucket:
diameter of 5 inches,
height of 4.6 inches
Large Bucket:
diameter of 6 inches,
height of 8 inches
The large bucket is how many times larger
when compared to the small bucket?
Round to the nearest hundredth.

Answer 1

The volume of a cylinder can be calculated using the formula V = πr^2h, where V is the volume, r is the radius, and h is the height. The radius is half of the diameter.

For the small bucket, the radius is 2.5 inches (half of 5 inches) and the height is 4.6 inches. So, the volume of the small bucket is π * 2.5^2 * 4.6 ≈ 90.2 cubic inches.

For the large bucket, the radius is 3 inches (half of 6 inches) and the height is 8 inches. So, the volume of the large bucket is π * 3^2 * 8 ≈ 226.19 cubic inches.

Therefore, when compared to the small bucket, the large bucket is 226.19 / 90.2 ≈ 2.51 times larger.

So, rounded to the nearest hundredth, the large bucket is 2.51 times larger than the small bucket.

Explanation: