Question

Find the 32nd term.
3, 7, 11, 15, 19, ...
32nd term =

Answer 1

127

Explanation:

The given sequence is an arithmetic sequence with a common difference of 4.

To find the 32nd term, we can use the formula for the nth term of an arithmetic sequence:

an = a1 + (n - 1)d

where an is the nth term, a1 is the first term, n is the number of terms, and d is the common difference.

In this case, a1 = 3, d = 4, and n = 32. Substituting these values into the formula, we get:

a32 = 3 + (32 - 1)4

a32 = 3 + 124

a32 = 127

Therefore, the 32nd term is 127.

Answer 2

T₃₂ = 127

Explanation:

3 , 7 , 11 , 15 , 19

First, let us find the common difference of this arithmetic sequence.

d = 7 - 3 = 4

And now let us use the below formula to find the 32nd term.

T n = a + ( n - 1 ) × d

Here,

a → first term → 3

d → common difference → 4

n → No. of terms → 32

Let us find it now.

T₃₂ = a + ( n - 1 ) × d

T₃₂ = 3 + ( 32 - 1 ) × 4

T₃₂ = 3 + 31 × 4

T₃₂ = 3 + 124

T₃₂ = 127