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Solve 3x²+7x-13 = 0 Give your solutions correct to 2 decimal places​
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Solve 3x²+7x-13 = 0 Give your solutions correct to 2 decimal places​

User Maged
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Answer:

Explanation:


3x^2+7x-13=0\\x = (-7 +- √(49+156) )/(6)\\ x = (-7 +- √(215) )/(6)\\ x = (-7)/(6)+-(14.66)/(6)\\ x = (7.66)/(6) = 1.27\\ or\\x = (-21.66)/(6) = -3.61

User Henz
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