Question

What is the equation, in slope-intercept form, of the line that is perpendicular to the line

y-4=(x-6) and passes through the point (-2,-2)?
0 y=-x-10
Oy=-3x+10
Oy=2x-1
O y = 2x+1

Answer 1

y = (3/2)x + 1

Explanation:

straight line equation format is y -y1 = m(x - x1)

where y1 is y-coordinate of a point, x1 is x-coordinate of the same point, m is the slope (gradient).

slope of y - 4 = -2/3 (x - 6) is -2/3, since that's the number before x.

this means that slope of perpendicular line = -(1/ (-2/3)) = 3/2.

it passes through (-2, -2)

equation is y - -2 = 3/2 (x - - 2)

y + 2 = 3/2 (x +2) = (3/2) x + 3

subtract 2 from both sides

y = (3/2)x + 1