Answer:
The equation of a line that is perpendicular to y = 3x + 3 is option A y equals negative one-third times x plus 1(-1/3x + 1)Given,The equation of line, y = 3x + 3The line passes through (-6, 3)We have to find the equation of the line that is perpendicular to y = 3x + 3Slope of the line, m = 3Here, in perpendicular case, slope is negative of its reciprocal.That is, m = -1/3Now, we can find the equationy - y₁ = m(x - x₁)
Here,
y₁ = 3x₁ = -6m = -1/3
So,y - 3 = -1/3(x - (-6))
y - 3 = -1/3(x + 6)
y - 3 = -1/3x + -1/3(6)
y - 3 = -1/3x - 6/3
y - 3 = -1/3
x - 2y = -1/3
x - 2 + 3
y = -1/3x + 1
That is, the equation of a line that is perpendicular to y = 3x + 3 is y equals negative one-third times x plus 1(y = -1/3x + 1)
Explanation: