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Solve the following inequality, indicate the number of solutions and plot the solutions on a number line.

d. 3(x + 3) + 12 ≤ 3x + 28

1 Answer

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Let's start by simplifying the left side of the inequality:

3(x+3) + 12 <= 3x + 28

3x + 9 + 12 <= 3x + 28

3x + 21 <= 3x + 28

Subtracting 3x from both sides, we get:

21 <= 28

This is a true statement, which means that the inequality is true for all values of x. In other words, there are infinitely many solutions.

To represent this graphically, we can draw a number line and shade in all values of x for which the inequality is true. Since it's true for all values of x, we shade in the entire number line:

<=======()------------------->

In this number line, the open circle () indicates that the inequality is not true for that particular value (in this case, there is no specific value for x that makes the inequality false). The arrow indicates that the inequality is true for all values of x to the left and right of the open circle.

In summary, the inequality 3(x+3)+12 <= 3x+28 is true for all values of x, and there are infinitely many solutions.

I'm 15 BTW

User Siddharth Thevaril
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