Question

2C3H6O + 8O2 --> 6CO2 + 6H2O

The combustion reaction for propanol is given above. How many moles of water are produced if 0.15 moles of propanol (C3H6O) reacts with an excess amount oxygen gas?


Please try to show work if possible!

Answer 1

Answer: 0.45 moles of
`H_2O` will be produced from 0.15 moles of propanol.

Step-by-step explanation:

The balanced chemical reaction is:

`2C_3H_6O+8O_2\rightarrow 6CO_2+6H_2O`

`C_3H_6O` is the limiting reagent as it limits the formation of product and
`O_2` is the excess reagent.

According to stoichiometry :

2 moles of
`C_3H_6O`produces = 6 moles of
`H_2O`

Thus 0.15 moles of
`V` will produce=
`(6)/(2)* 0.15=0.45moles` of
`H_2O`

Thus 0.45 moles of
`H_2O` will be produced from 0.15 moles of propanol.