165k views
4 votes
An urn contains 6 red beads, 4 blue beads, and 2 green beads. If a single bead is picked at random, what is the probability that the bead is blue?

Give your answer as a fraction.

2 Answers

2 votes

Answer:

Step-by-step explanation: 6 + 4 + 2 = 12 (denominator)

Put 4 (blue beads) in numerator

4/12 reduces to 1/3

Final answer is 1/3

User Lczapski
by
7.9k points
5 votes


|\Omega|=6+4+2=12\\|A|=4\\\\P(A)=(4)/(12)=(1)/(3)\approx33.3\%

User Svk
by
8.0k points
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