Answer:
y = 5(x - 3)^2 - 4 + c
Explanation:
The standard form of a quadratic function is y = ax^2 + bx + c, where a, b, and c are constants. To shift the graph three units to the right and four units down, we can modify the constant term c and the linear term bx:
y = a(x - 3)^2 - 4 + c
To make it five times narrower, we can modify the coefficient of the squared term a:
y = (1/5)a(x - 3)^2 - 4 + c
Since we want the shape to be the same as y = x^2, we can set a = 5:
y = 5(x - 3)^2 - 4 + c
The value of c will depend on the specific context of the problem or graph.