Question

PLS HELP ME
ONLY PEOPLE WITH REAL AWNSERS!!

Answer 1

7:20

I think

T-T

Answer 2

7:20 p.m.

Explanation:

First, we can find the distance that each friend will be from their house at the time when they meet each other.

To find this, we can multiply the ratio
`8 \text{ mi} : 7 \text{ mi}` by a constant such that the sum of both numbers in the ratio is 20, since the friends' houses are 20 miles apart. Solving for this constant:

`(20)/(7 + 8) \\ \\ = (20)/(15) \\ \\ \boxed{=(4)/(3)}`

Multiplying the constant by both sides of the ratio:

`(4)/(3)\left(8 \text{ mi}) : (7 \text{ mi}\right)(4)/(3)`

`\boxed{= (32)/(3) \text{ mi} : (28)/(3) \text{ mi}\right)}`

So, we know that the first friend will have traveled 32/3 or 10 2⁄3 miles when they meet, and the second friend will have traveled 28/3 or 7 1⁄3 miles.

Now, to calculate what time they will meet, we can divide how far one of the friends has traveled by how fast they were traveling. This will give us the minutes it will take them to get to the meeting place. We can then add that amount of minutes to 6:00 p.m. to calculate when they will meet.

I will use the fast friend (traveling at 8 mph).

`(32)/(3) \text{ mi} \cdot \frac{60 \text{ min}}{8 \text{ mi}}`

— Also note that I substituted 1 hour for 60 minutes in the mph ratio.

`= (32)/(3) \\ot\text{mi} \cdot \frac{60 \text{ min}}{8 \\ot\text{mi}}`

`= (32 \cdot 60)/(3 \cdot 8) \text{ min}`

`= (32)/(8) \cdot (60)/(3) \text{ min}`

`= 4 \cdot 20 \text{ min}`

`\boxed{= 80\text{ min}}`

Adding those minutes to 6:00, noting that 80 min = 1 hr 20 min:

`\text{ } \ \, 6\!:\!00 \text{ p.m.}\\\underline{+ 1\!:\!20}\\\\\text{ }\, \boxed{7\!:\!20 \text{ p.m.}}`

So, the friends will meet at 7:20 p.m.