Answer:
The pH at the equivalence point is 7.00.
When 25.00 mL of 0.1000 M CH3COOH is titrated with 0.1000 M NaOH, the reaction is:
CH3COOH + NaOH → CH3COO- + H2O
At the equivalence point, the number of moles of CH3COOH is equal to the number of moles of NaOH. This means that the concentration of CH3COO- is equal to the concentration of H+.
The pKa of CH3COOH is 4.75. This means that the pH at the equivalence point is 14 - pKa = 7.00.
Here is the calculation:
pH = -log[H+]
pH = -log[10^(-4.75)]
pH = 7.00
Step-by-step explanation: