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3 votes
One cloud carries a charge of -1.0 C and another cloud carries a charge

of 5.0 C. The two clouds are 1.5 x 10³ m apart.
Calculate the magnitude of the force between these two charged objects
Write your answer in scientific notation using two significant figures.
N
1/3
Let's use Coulomb's law to calculate the force between the
charged objects:
|FE| = k
9192
p2

One cloud carries a charge of -1.0 C and another cloud carries a charge of 5.0 C. The-example-1

2 Answers

3 votes

Final answer:

To calculate the magnitude of the force between two charged objects, we can use Coulomb's law. In this case, the magnitude of the force is 1.034 * 10^4 N.

Step-by-step explanation:

To calculate the magnitude of the force between two charged objects, we can use Coulomb's law which is given by |FE| = k * |q1*q2| / r^2, where k = 9.192 * 10^9 Nm^2/C^2 is the electrostatic constant, q1 and q2 are the charges of the two objects, and r is the distance between them.

In this case, q1 = -1.0 C, q2 = 5.0 C, and r = 1.5 * 10^3 m. Plugging in these values into the formula, we get |FE| = (9.192 * 10^9 Nm^2/C^2) * (|-1.0 C * 5.0 C| / (1.5 * 10^3 m)^2).

Simplifying the expression, we have |FE| = (9.192 * 10^9 Nm^2/C^2) * (5.0 C^2 / (1.5 * 10^3 m)^2).

Calculating the numerical value, we get |FE| = 1.034 * 10^4 N.

User Chiragkyada
by
8.4k points
4 votes

Using Coulomb's law, the magnitude of the force (|FE|) between the two charged clouds can be calculated as:

|FE| = k * (|q1| * |q2|) / r^2

where k is Coulomb's constant, |q1| and |q2| are the magnitudes of the charges on the two clouds, and r is the distance between them.

Substituting the given values, we get:

|FE| = (9 x 10^9 N m^2/C^2) * (|-1.0 C| * |5.0 C|) / (1.5 x 10^3 m)^2

|FE| = (9 x 10^9 N m^2/C^2) * (5.0) / (1.5 x 10^3 m)^2

|FE| = 15 x 10^6 N

To express this answer in scientific notation with two significant figures, we can write:

|FE| = 1.5 x 10^7 N (rounded to two significant figures)

Therefore, the magnitude of the force between the two charged clouds is 1.5 x 10^7 N.

User Bea
by
8.6k points