Question

Solve the equation on the interval [0, 2π). sin2 x - cos2 x = 0

Answer 1

pi/8 + k(pi/2)

Explanation:

2x=t

sint - cost = 0

sint/cost - cost/cost = 0

tant = 1

t= pi/4 + k(pi) = 2x

x = pi/8 + k(pi/2)

[0;2pi]

x= pi/8

x= pi/8 + pi/2 = 5pi/8

x= 9pi/8

x= pi/8 + 3pi/2 = 13pi/8