Question

HELPPPP

find three consecutive integers such that the sum of twice the second and three times the third is five less than six times the first.

Answer 1

13, 14, 15

Explanation:

The three integers are consecutive so let those integers be x, (x+1), (x+2)

As per the question,

2(x+1) + 3(x+2) = 6x-5

or, 2x+1+3x+6 = 6x-5

or, 8+5 = 6x-5x

or, x = 13

So, x+1 = 13+1 = 14

x+2 = 13+2 = 15