Question

suppose an irregular 4-sided solid object, having sides numbered 1 through 4, is rolled 100 times, and side 3 turns up 28 times. what is the approximate probability of this event happening?

Answer 1

Answer: P(X=28) ≈ C(100, 28) * (1/4)^28 * (3/4)^72 ≈ 0.0368 (rounded to 4 decimal places)

Explanation:

Using the binomial probability formula:

P(X=k) = C(n, k) * p^k * (1-p)^(n-k)

Where:

n = 100 (number of trials)

k = 28 (number of successes)

p = 1/4 (probability of success for each trial, since there are 4 sides)

C(n, k) = n! / (k! * (n-k)!)

Plugging the values:

P(X=28) ≈ C(100, 28) * (1/4)^28 * (3/4)^72 ≈ 0.0368 (rounded to 4 decimal places)