The charge will move against the direction of the force.
What is the magnitude of the force on a -30.0 nC charge
To find the magnitude of the force on a -30.0 nC charge placed inside a uniform electric field of 7.00 x 10^8 N/C, we can use the formula:
F = qE
where F is the magnitude of the force, q is the charge, and E is the electric field.Plugging in the given values, we get:
F = (-30.0 x 10^-9 C) x (7.00 x 10^8 N/C) = -2.10 x 10^-2 N
The negative sign indicates that the force is in the opposite direction to the direction of the electric field.
Since the force is negative, it means that the n the opposite direction of the electric field. Therefore, the charge wiforce is acting ill move against the direction of the force.
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