1. Using Boyle's Law: V₂ = V₁(P₁/P₂) = 10 L * (174 atm/4 atm) = 435 L. Therefore, the scuba tank would be able to deliver 435 L of air to a diver at a depth of 30 m.
2. Using Charles's Law: (P₂/T₂) = (P₁/T₁) where P₁ = 174 atm and T₁ = 294K (21°C + 273.15) and T₂ = 276K (3°C + 273.15). Solving for P₂, we get P₂ = (P₁/T₁) * T₂ = (174 atm/294K) * 276K = 164 atm. Therefore, the pressure of the gas in the tank while it was in the room was approximately 164 atm.