Answer:
a] 24.5; b] 2.8; c] 39.59.
Explanation:
a. after t=1sec:
h(1)=-4.9*1²+27*1+2.4; ⇔h(1)=24.5 [m];
b. more than 30 [m] heigh:
-4.9t²+27t+2.4≥30; ⇔ 4.9t²-27t+27.6≤0; ⇔(t-1.35)(t-4.15)≤0;
Δt≈4.15-1.35=2.8 [sec];
c. maximum height:
h'(t)=-9.7t+27; ⇒ h'(t)=0, ⇒ -9.7(t-2.78)=0; ⇒ t=2.78 [sec], then
![h_(max)=h(2.78)=-4.9*2.78^2+27*2.78+2.4=39.59[m].](https://img.qammunity.org/2024/formulas/mathematics/college/pq3b7ns2lrkhtg4v5mmmfi1jy4yf683a20.png)