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find the product (k-1) (6k+5)

A.6k²-5
B.6K²-11K-5
C.6k²-k-5
D.6K²+11K-5

User Gnodab
by
7.8k points

1 Answer

7 votes

Answer:

C

Explanation:

(k - 1)(6k + 5)

each term in the second factor is multiplied by each term in the first factor , that is

k(6k + 5) - 1(6k + 5) ← distribute parenthesis

= 6k² + 5k - 6k - 5 ← collect like terms

= 6k² - k - 5

User Berta
by
8.2k points
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