Question

Formula: E(eV) = 1240/λ(nm) Suppose the bandgap of a certain semiconductor is 1.6 eV. What is the maximum wavelength absorbed by this material?

Answer 1

The maximum wavelength absorbed by a semiconductor with a bandgap of 1.6 eV is 775 nm.

Step-by-step explanation:

To find the maximum wavelength absorbed by a semiconductor with a bandgap of 1.6 eV, we can use the formula:

E(eV) = 1240/λ(nm)

Given that the bandgap is 1.6 eV, we can substitute it into the formula to solve for λ:

E(eV) = 1.6 eV

1.6 eV = 1240/λ(nm)

Now we can solve for λ by rearranging the equation:

λ(nm) = 1240/1.6 = 775 nm

Therefore, the maximum wavelength absorbed by this material is 775 nm.

Answer 2

The maximum wavelength absorbed by the material is 775 nm.

Step-by-step explanation:

Formula: E(eV) = 1240/λ(nm)

If the bandgap of a certain semiconductor is 1.6 eV, we can use the formula to find the maximum wavelength absorbed by this material. Plugging in the given value of E(eV) = 1.6, we can rearrange the formula to solve for λ(nm). So, λ(nm) = 1240/E(eV) = 1240/1.6 = 775 nm.

Therefore, the maximum wavelength absorbed by this material is 775 nm.