Question

What is the mass of a piece of iron that releases 188.90 joules of heat as it cools from 75.66 degrees Celsius to 35.47 degrees Celsius? The specific heat of iron is 0.450 J/gC; please answer to two digits after the decimal point.

Answer 1

To solve the problem, we can use the formula:

q = m × c × ΔT

where q is the heat energy released, m is the mass of the iron, c is the specific heat of iron, and ΔT is the change in temperature.

Substituting the given values and solving for m, we get:

q = m × c × ΔT

188.90 J = m × 0.450 J/g°C × (75.66°C - 35.47°C)

188.90 J = m × 0.450 J/g°C × 40.19°C

m = 188.90 J / (0.450 J/g°C × 40.19°C)

m = 9.96 g

Therefore, the mass of the piece of iron is 9.96 g.