58.9k views
0 votes
HELP AS SOON AS POSSIBLE PLEASE.

HELP AS SOON AS POSSIBLE PLEASE.-example-1
User Dungeon
by
8.7k points

2 Answers

5 votes

Answer:

Answer for 13. :


(1)/(3) ft

Answer for 14. :


162√(2) - 81 cm^2

User Prijin Koshy Alex
by
7.1k points
7 votes

Answer:

13) 8.7 ft²

14) 114.6 cm²

Explanation:

Question 13

The area of the shaded region can be calculated by subtracting the area of the hexagon from the area of the circle.

The formulas for the area of a circle and the area of a regular hexagon are:


\boxed{\begin{minipage}{3.9 cm}\underline{Area of a circle}\\\\$\vphantom{(3√(3))/(2) }A=\pi r^2$\\\\where $r$ is the radius.\\\end{minipage}}
\boxed{\begin{minipage}{4.1 cm}\underline{Area of a regular hexagon}\\\\$A=(3√(3))/(2) r^2$\\\\where $r$ is the radius.\\\end{minipage}}

The circle and hexagon both have a radius of 4 ft.

Therefore:


\begin{aligned}\textsf{Shaded area}&=\pi r^2 - (3√(3))/(2)r^2\\\\&=\pi \cdot 4^2 - (3√(3))/(2)\cdot 4^2\\\\&=16\pi - (3√(3))/(2) \cdot 16\\\\&=16\pi - (48√(3))/(2) \\\\&=16\pi - 24√(3)\\\\&=8.69626307...\\\\&=8.7\; \sf ft^2\end{aligned}

Therefore, the area of the shaded region is 8.7 ft² (nearest tenth).


\hrulefill

Question 14

The shaded region is made up of 4 congruent isosceles triangles.

The apex angle of each triangle is the interior angle of a regular octagon, 135°, and the congruent sides measure 9 cm.

The formula for an isosceles triangle is


\boxed{\begin{minipage}{8 cm}\underline{Area of an isosceles triangle}\\\\$A=(1)/(2)s^2 \sin \theta$\\\\where:\\ \phantom{w} $\bullet$ $s$ is the congruent side length.\\\phantom{w} $\bullet$ $\theta$ is the angle between the congruent sides.\\\end{minipage}}

Therefore, the area of the shaded region is:


\begin{aligned}\textsf{Shaded area}&=4 \cdot (1)/(2) \cdot 9^2 \cdot \sin 135^(\circ)\\\\&=4 \cdot (1)/(2) \cdot 81 \cdot (√(2))/(2)\\\\&=2\cdot 81 \cdot (√(2))/(2)\\\\&=162 \cdot (√(2))/(2)\\\\&=81√(2)\\\\&=114.6\; \sf cm^2\;(2\;d.p.)\end{aligned}

Therefore, the area of the shaded region is 114.6 cm² (nearest tenth).

User Brunilda
by
7.6k points