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4x^3 + 0x^2 -3x +4
2x -5

User Strave
by
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1 Answer

2 votes

Assuming you want to divide 4x^3 + 0x^2 - 3x + 4 by 2x - 5 using polynomial long division:

2x^2 + 4x + 7

---------------------

2x - 5 | 4x^3 + 0x^2 - 3x + 4

- (4x^3 - 10x^2)

---------------

10x^2 - 3x

- (10x^2 - 25x)

---------------

22x + 4

Therefore, the quotient is 2x^2 + 4x + 7 and the remainder is 22x + 4.

Thus, we can write:

4x^3 + 0x^2 - 3x + 4 = (2x - 5)(2x^2 + 4x + 7) + (22x + 4)

So the division of the polynomial 4x^3 + 0x^2 - 3x + 4 by 2x - 5 results in the quotient 2x^2 + 4x + 7 and the remainder 22x + 4.

User Glauco Cucchiar
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