Answer: The capacitance of the capacitor is 0.375 µF. The energy stored in it is 300 µJ.
Step-by-step explanation: The capacitance (C) of a capacitor is given by the equation:
C = Q/V
where Q is the charge stored on the capacitor and V is the voltage across the capacitor. Using the given values, we can calculate the capacitance as:
C = Q/V = 15 µC / 40 V = 0.375 µF
Therefore, the capacitance of the capacitor is 0.375 µF.
The energy (U) stored in a capacitor is given by the equation:
U = (1/2) * C * V^2
where C is the capacitance and V is the voltage across the capacitor. Using the given values, we can calculate the energy stored in the capacitor as:
U = (1/2) * C * V^2 = (1/2) * 0.375 µF * (40 V)^2
U = (1/2) * 0.375 * 1600
U = 300 µJ
Therefore, the energy stored in the capacitor is 300 µJ.